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Question

Find the mean deviation about mean and median for the following data.
CI5101015152020252530
f5123119

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Solution

CIfi cf Midpoint
xi
|xiM| fi|xiM|
5105 5 7.5 12.5 62.5
1015 12 17 12.5 7.590
1520 3 20 17.52.5 7.5
2025 11 31 22.52.5 27.5
2530 9 40 27.5 7.5 67.5
fi=40 fi|xiM|=255
Here, N2=402=20
Median class =1520
So, L=15,cf=17,f=3 and h=2015=5
Median(M)=L+N2cff×h
=15+20173×5
=15+5
=20
Median (M)=20
Mean deviation about the mean =fi|xiM|fi
=25540
=6.37



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