Find the mean of the observations $425, 430, 435, 440, 445, . . . . . . . . . . . 495.$

420

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425

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435

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460

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Solution

The correct option is D $460$
No. of observations $= 15$
Sum of observations $= 425 + 430 + 435 + 440 + 445 + 450 + 455 + 460 + 465 + 470 + 475 + 480 + 485$
$+ 490 + 495 = 6900$

Mean $= \frac{6900}{15} = 460$

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Find the mean of the observations 425,430,435,440,445,...........495.

The correct option is D 460No. of observations=15Sum of observations=425+430+435+440+445+450+455+460+465+470+475+480+485+490+495=6900Mean=690015=460

Find the mean of the observations $425, 430, 435, 440, 445, . . . . . . . . . . . 495.$

The correct option is D $460$
No. of observations $= 15$
Sum of observations $= 425 + 430 + 435 + 440 + 445 + 450 + 455 + 460 + 465 + 470 + 475 + 480 + 485$
$+ 490 + 495 = 6900$

Mean $= \frac{6900}{15} = 460$