Find the mean using step-deviation- - Class Interval Frequency- 35-45 200- 45-55 250- 55-65 50- 65-75 70- 75-85 40- - -4 MARKS-

Table: 2 Marks Application: 2 Marks Let the assumed mean be 60. Class size = 10 [ x_i amp; f_i amp; d_i amp; u_i amp; f_iu_i; 40 ...

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Standard X

Mathematics

Measure of Dispersion

Find the mean...

Question

Find the mean using step-deviation.
$\begin{matrix} C l a s s I n t e r v a l & F r e q u e n c y 35 - 45 & 200 45 - 55 & 250 55 - 65 & 50 65 - 75 & 70 75 - 85 & 40 \end{matrix}$ [4 MARKS]

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Solution

Table: 2 Marks
Application: 2 Marks

Let the assumed mean be 60.

Class size = 10

$\begin{matrix} x_{i} & f_{i} & d_{i} & u_{i} & f_{i} u_{i} 40 & 200 & -20 & -2 & -400 50 & 250 & -10 & -1 & -250 60 & 50 & -0 & 0 & 0 70 & 70 & 10 & 1 & 70 80 & 40 & 20 & 2 & 80 \end{matrix}$

$\sum f_{i} = 610$

$\sum f_{i} u_{i} = - 500$

Mean
$= 60 + (\frac{- 500}{610} \times 10)$

$= 60 - 8.20$

$= 51.80$

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Find the mean using step-deviation. Class IntervalFrequency35−4520045−5525055−655065−757075−8540 [4 MARKS]

Table: 2 Marks Application: 2 Marks Let the assumed mean be 60. Class size = 10 xifidiuifiui40200-20-2-40050250-10-1-2506050-000707010170804020280 ∑fi=610 ∑fiui=−500 Mean =60+(−500610×10) =60−8.20 =51.80

Find the mean using step-deviation.
$\begin{matrix} C l a s s I n t e r v a l & F r e q u e n c y 35 - 45 & 200 45 - 55 & 250 55 - 65 & 50 65 - 75 & 70 75 - 85 & 40 \end{matrix}$ [4 MARKS]