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Question

Find the nitrogen percentage in [CO(NH2)2]:

A
23
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B
28
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C
46.67
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D
25
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Solution

The correct option is C 46.67
Total molecular weight of compound [CO(NH2)2]:
=12+16+2(14+2)=60
Weight of 2 moles of N in molecule =2×14=28
Nitrogen content of molecule=2860×100=46.67%

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