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Question

Find the order and degree of the differential equation d2ydx2=[1+(dydx)2]32.

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Solution

The given differential equation
d2ydx2=[1+(dydx)2]32,
can be written as
(d2ydx2)2=[1+(dydx)2]3
From the equation it is clear second order derivative involved in the equation, so the order is 2 and power of the highest ordered term is 2 so the degree of the differential equation is 2.

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