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Byju's Answer
Standard VII
History
Shahajiraje and Jijabai
Find the smal...
Question
Find the smallest number which, when increased by one is exactly divisible by
12
,
18
,
24
,
32
and
40.
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Solution
Step: Find the smallest number
L
.
C
.
M
.
of given numbers
∴
L
.
C
.
M
.
=
2
×
2
×
2
×
2
×
2
×
3
×
3
×
5
=
1440
∴
The smallest number
=
1440
−
1
=
1439
Hence, the smallest number is
1439
.
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Shahajiraje and Jijabai
Standard VII History
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