Find the smallest number which when reduced by 2 is divisible by 5 and 7.

The correct option is C 37
The LCM of 5 and 7 is:
$\begin{array}{cc}& 5,7\\ & \end{array}$
LCM = 5 × 7
= 35

35 is the smallest number that is divisible by both 5 and 7.
Adding 2 to it will give us the required number which is 37.