Find the smallest square number that is divisible by each of the numbers $8$, $15$ and $20$.

The correct option is B 3600

L.C.M of 8, 15 and 20 is (2 $\times$ 2 $\times$ 5 $\times$ 2 $\times$ 3) = 120.
120 = (2 $\times$ 2) $\times$ 5 $\times$ 2 $\times$ 3
Here, 5, 2 and 3 are not paired.
Therefore, we need to multiply 120 by (5 $\times$ 2 $\times$ 3) i.e. 30 to get a perfect square.
Hence, the smallest squared number which is divisible by numbers 8, 15 and 20 = 120$\times$ 30 = $3600$