Find the smallest three digit number that is divisible by both 2 and 3.

1. 102

The correct option is A 102
Divisibility by 2: Last digit of the number should be even.
3 digit numbers that are divisible by 2 in ascending order: 100, 102, 104 and so on.
Divisibility by 3: Sum of the digits of the number must be divisible by 3.
For 102, sum of the digits (1+ 0 + 2 = 3) is divisible by 3. Hence, 102 is the required answer.