Find the value of $k$ for which the following system of equations has no solution:
$2x-ky+3=0$
$3x+2y-1=0$

For the system of equations to have no solution, the lines must be parallel.

$\Rightarrow$The ratio of '$x$' and '$y$' coefficients must be equal.

$\Rightarrow \frac{2}{3}=\frac{-k}{2}$

$\Rightarrow k=\frac{-4}{3}$