Find the value of:
$\left(ii\right)3a-2b$, when $a=8$ and $b=10$

Substituting $a=8,b=10$ in $(3a-2b)$, we get:
$(3a-2b)=3\left(8\right)–2\left(10\right)$
$=24-20$
$=4$
Therefore, the value of $(3a-2b)$ is $4$