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Question
Find the velocity of images formed due to a point object O w.r.t. ground if the mirror is at rest. All speeds given are w.r.t a stationary ground observer
Find the velocity of images formed due to a point object O w.r.t. ground if the mirror is at rest. All speeds given are w.r.t a stationary ground observer
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Solution
The correct option is B 45 m/s towards mirror
For the velocity component along the principal axis, (VIM)=−v2u2(VOM)
where VIM=Velocity of image w.r.t mirror.
VOM=Velocity of object w.r.t mirror.
Apply mirror equation:
1v+1u=1f⇒1v+1−20=1−30⇒v=+60 cm⇒m=−vu=−60−20=3
Since mirror is at rest (given that):
(VIM)=−(3)2×(VOM)=−9×5=−45 m/s⇒→VIG=→VIM+→VMG =−45+0=−45 m/s
That means images approaches the mirror with velocity 45 m/s.
For the velocity component along the principal axis, (VIM)=−v2u2(VOM)
where VIM=Velocity of image w.r.t mirror.
VOM=Velocity of object w.r.t mirror.
Apply mirror equation:
1v+1u=1f⇒1v+1−20=1−30⇒v=+60 cm⇒m=−vu=−60−20=3
Since mirror is at rest (given that):
(VIM)=−(3)2×(VOM)=−9×5=−45 m/s⇒→VIG=→VIM+→VMG =−45+0=−45 m/s
That means images approaches the mirror with velocity 45 m/s.
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