Find the volume of Iron required to make an open box whose external dimensions are 36 cm - 25 cm - 16-5 cm - the box being 1-5 cm thick throughout- if 1 cm3 of iron weighs 8-5 grams- find the weight of the empty box in kilograms-

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Standard VIII

Mathematics

Volume of a Cuboid

Find the volu...

Question

Find the volume of Iron required to make an open box whose external dimensions are 36 cm $\times$ 25 cm $\times$ 16.5 cm , the box being 1.5 cm thick throughout. if 1 cm3 of iron weighs 8.5 grams, find the weight of the empty box in kilograms.

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Solution

Outer length of open box =36 cm

Breadth =25 cm

and height =16.5 cm.

thickness of iron =1.5 cm.

$∴$ Inner length $= 36 - 2 \times 1.5 = 36 - 3 = 33 c m$

breadth $= 25 - 2 \times 1.5 = 25 - 3 = 22 c m$

and height =16.5-1.5 =15 cm

$∴$ Volume of iron used in it

=Outer volume -Inner volume

$= 36 \times 25 \times 16.5 c m^{3} - 33 \times 22 \times 15 c m^{3}$

$= 14850 - 10890 = 3960 c m^{3}$

weight of $1 c m^{3} = 8.5$ gram

$∴$ Total weight $= 3960 \times 8.5 g$

=33660 g =33.660 kg

=33.66 kg

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Q. How many cubic centimetres of iron is required to construct an open box whose external dimensions are

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and

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provided the thickness of the iron is

1.5 c m

How many cubic centimetres of iron are there in an open box whose external dimensions are 36 cm, 25 cm and 16.5 cm, the iron being 1.5 cm thick throughout? If 1 cubic cm of iron weighs 15 g, find the weight of the empty box in kg.

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Find the volume of Iron required to make an open box whose external dimensions are 36 cm × 25 cm × 16.5 cm , the box being 1.5 cm thick throughout. if 1 cm3 of iron weighs 8.5 grams, find the weight of the empty box in kilograms.

Find the volume of Iron required to make an open box whose external dimensions are 36 cm $\times$ 25 cm $\times$ 16.5 cm , the box being 1.5 cm thick throughout. if 1 cm3 of iron weighs 8.5 grams, find the weight of the empty box in kilograms.