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Salt of Strong Acid and Strong Bases

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Question

Find the weight of $N a N O_{3}$ in grams (Rounded off to nearest integer), required to make 50 mL of an aqueous solution containing 70 mg per mL of $N a^{+}$ ions

[Given:Atomic weight in $g m o l^{- 1} [N a : 23; N : 14; O : 16]$

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Solution

$Concentration of N a^{+} = 70 m g / m L$
$W_{N a}$ in 50 mL solution:
$70 \times 50 m g = 3500 m g = 3.5 g$
$Moles of N a^{+} in 50 mL solution = \frac{3.5}{23} m o l$
$N a N O_{3} (a q) \to N a^{+} (a q) + N O_{3}^{-} (a q)$
$Moles of N a N O_{3} = Moles of N a^{+} = \frac{3.5}{23} m o l$
$Mass of N a N O_{3} = \frac{3.5}{23} \times 85 = 12.94 \approx 13 g$

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