For the t62ge2g system- the value of magnetic moment - is

In the given configuration (t^6_2ge^2_g), number of unpaired electron is 2. n=2 for spin only magnetic moment, μ=√(n(n+2))=√(2(2+2)) μ=√(8)=2.83 B.M ...

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Standard XII

Chemistry

Lanthanides Electronic Configuration

For the t62ge...

Question

For the $t_{2 g}^{6} e_{g}^{2}$ system, the value of magnetic moment $(μ)$ is

2.83 B . M .

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1.73 B . M .

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3.87 B . M .

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4.92 B . M .

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Solution

The correct option is A $2.83 B . M .$
In the given configuration $(t_{2 g}^{6} e_{g}^{2})$ , number of unpaired electron is 2.
n=2
for spin only magnetic moment,
$μ = \sqrt{n (n + 2)} = \sqrt{2 (2 + 2)}$
$μ = \sqrt{8} = 2.83 B . M$

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For the t62ge2g system, the value of magnetic moment (μ) is

The correct option is A 2.83 B.M.In the given configuration (t62ge2g), number of unpaired electron is 2. n=2 for spin only magnetic moment, μ=√n(n+2)=√2(2+2) μ=√8=2.83 B.M

For the $t_{2 g}^{6} e_{g}^{2}$ system, the value of magnetic moment $(μ)$ is

The correct option is A $2.83 B . M .$
In the given configuration $(t_{2 g}^{6} e_{g}^{2})$ , number of unpaired electron is 2.
n=2
for spin only magnetic moment,
$μ = \sqrt{n (n + 2)} = \sqrt{2 (2 + 2)}$
$μ = \sqrt{8} = 2.83 B . M$