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Question

Force (F) acting on a particle varies will displacement (x) as shown in figure. The work done by this force on the particle from x=0 to x=6 m is:
1022212_fac2542ce569488fac6d68e05d8f84c5.png

A
20 J
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B
40 J
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C
50 J
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D
60 J
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Solution

The correct option is B 40 J
Work done by the given force = area under the graph
= area of rectangle + area of 1st triangle + area of 2nd triangle.
=[(100)×(40)]+[12×(54)×(100)]+[12×(65)×(100)]=[10×4]+[12×1×10]+[12×1×10]=40+5+(5)=40J

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