You visited us 2 times! Enjoying our articles? Unlock Full Access!

Action of Water on Calcium Carbide

Formation of ...

Question

Formation of acetylene from calcium acetylide can be represented as
$C a^{2 +} C \equiv C^{2 -} + 2 H_{2} O \to H - C \equiv C - H + 2 O H^{-} + C a^{2 +}$

The stronger acid (acetylene) is displaced from its salt by a relatively weaker acid (water)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The weaker acid (acetylene) is displaced from its salt by a relatively stronger acid (water)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The weak acid (acetylene) is displaced from its salt by anothr weaker acid (water).

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The weaker acid (acetylene) is displaced from its salt by neutral substance (water)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B The weaker acid (acetylene) is displaced from its salt by a relatively stronger acid (water)
Acetylene is a weaker acid than water since the extent of dissociation is relatively low. So, the correct answer will be option (b).

Suggest Corrections

Similar questions

C a^{2 +} C \equiv C^{2 -} + 2 H_{2} O \to H - C \equiv C - H + 2 O H^{-} + C a^{2 +}

C a C_{2} + H_{2} O \to C_{2} H_{2} + C a {(O H)}_{2}

C_{2} H_{2}

C_{2} H_{2}

0.200 m o l

C a C_{2}

{C a C}_{2}

150 g

C_{2} H_{2}

C a C_{2} + 2 H_{2} O ⟶ C a {(O H)}_{2} + C_{2} H_{2}

C_{2} H_{2} + H_{2} ⟶ C_{2} H_{4}

n C_{2} H_{4} ⟶ {(- C H_{2} - C H_{2} -)}_{n}

C a C_{2}

C a C_{2} + 2 H_{2} O \to C a {(O H)}_{2} + C_{2} H_{2}

C_{2} H_{2}

C a C_{2}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program