Four particles A-B-C and D are situated at the vertices of a square of side -a- at t-0 - Each of the particles move with a constant speed -v- such that A aims towards B- B aims towards C- C aims towards D and D aims towards A- thenA- Particles will meat at center of square at t -2 a - vB- Particles will meat at center of square at t - a - vC- Distance travelled by any particle before meeting at center is vtD- Speed of approach of A and B is -2 v

Speed of approach is V_app = v By nbsp;V_app = Seperation/time V = a/t⇒ t = a/v By Speed = Distance/Time = Distance = vt ...

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Standard XII

Physics

Relative Velocity

Four particle...

Question

Four particles A,B,C and D are situated at the vertices of a square of side 'a' at t = 0. Each of the particles move with a constant speed 'v' such that A aims towards B, B aims towards C, C aims towards D and D aims towards A, then

Particles will meat at center of square at

t = \frac{\sqrt{2} a}{v}

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Particles will meat at center of square at

t = \frac{a}{v}

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Distance travelled by any particle before meeting at center is

v t

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Speed of approach of A and B is

\sqrt{2} v

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Solution

The correct option is C Distance travelled by any particle before meeting at center is $v t$

Speed of approach is $V_{a p p} = v$
By $V_{a p p} = \frac{Seperation}{time}$
$V = \frac{a}{t} \Rightarrow t = \frac{a}{v}$
By $Speed = \frac{Distance}{Time} = Distance = v t$

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Four particles A,B,C and D are situated at the vertices of a square of side 'a' at t = 0. Each of the particles move with a constant speed 'v' such that A aims towards B, B aims towards C, C aims towards D and D aims towards A, then

The correct option is C Distance travelled by any particle before meeting at center is vt Speed of approach is Vapp=v By Vapp=Seperationtime V=at⇒t=av By Speed=DistanceTime=Distance=vt

The correct option is C Distance travelled by any particle before meeting at center is $v t$

Speed of approach is $V_{a p p} = v$
By $V_{a p p} = \frac{Seperation}{time}$
$V = \frac{a}{t} \Rightarrow t = \frac{a}{v}$
By $Speed = \frac{Distance}{Time} = Distance = v t$