Frequency of an autosomal recessive lethal gene is $0.4$. Frequency of carrier in a population of $200$ individuals is?

The correct option is A $96$

The frequency of the recessive allele is $q=0.4$ (given)

Hence, $p=1-0,4=0.6$ (as p = 1- q)

According to Hardy- Weinberg principle, $p^2$ + $2pq$ + $q^2$ =$1$

hence, $p^2=(0.6{)}^2=0.36$

$q^2=(0.4{)}^2=0.16$

$2pq=0.48$

since, $2pq$ is the frequency of hetrozygous carrier,

= $0.48\times 200$

= $96$ Individuals

So, the correct answer is${}^{\prime }{96}^{\prime }$.