From a balloon rising vertically upwards at $5m/s$ a stone is thrown up at $10m/s$ relative to the balloon. Its velocity with respect to ground after $2s$ is (Take $g=10m/s^2$)

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A man in a balloon throws a stone downwards with a speed of 5 m/s with respect to balloon. The balloon is moving upwards with a constant acceleration of $5m/s^2$Then velocity of the stone relative to the man after 2 second is

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Two particles A and B are thrown vertically upward with velocity, 5 m/s and 10 m/s respectively ($g=10m/s^2$). Find separation between them after one second.

Q. A balloon is rising vertically up at constant speed $10m/s$. A stone is dropped from it when the balloon is at a height of $40m$. Total distance covered by the stone before reaching the ground is $(takeg=10m/s^2)$

Q. A balloon is rising vertically upwards at a velocity of $10m/s$ . When it is at a height of $45m$ from the ground,a parachutist bails out from it. After $3seconds$ he openshis parachute and decelerates at a constant rate of $5m/s^{-2}$. What was the height of the parachutist above the ground when he opened his parachute?(take $g=10m/s^{-2})$

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Two particles A and B are thrown vertically upward with velocity, 5 m/s and 10 m/s respectively ($g=10m/s^2$). Find separation between them after one second. (Use relative motion approach)