From a point source a light falls on a spherical glass surface (μ=1.5andradiusofcurvature=10cm). The distance between point source and glass surface is 50 cm . The position of image is
A
25 cm
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B
50 cm
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C
100 cm
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D
150 cm
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Solution
The correct option is A 50 cm Using, μ2v−μ1u=μ2−μ1R Here, μ1=1,μ2=1.5,u=−50cm ∴1.5v−1−50=1.5−110;1.5v=0.05−0.02=0.03 ⇒v=50cm