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Conductance of Electrolytic Solution

from the foll...

Question

from the following molar conductivities at infinite dilution molar conductivity of AL2(SO4)3 = 858 S cm2 mol -1 NH4OH = 238.3 S cm 2 mol -1 NH2(SO4)= 238.4 S cm2 mol -1 Calculate molar conductivity for AL(OH)3

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Solution

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A_{m}^{\infty} (H C l) = 126.4 Ω^{- 1} {c m}^{2} {m o l}^{- 1}

A_{m}^{\infty} (N a C l) = 425.9 Ω^{- 1} {c m}^{2} {m o l}^{- 1}

A_{m}^{\infty} ({C H}_{3} C O O N a) = 91 Ω^{- 1} {c m}^{2} {m o l}^{- 1}

(i n Ω^{- 1} {c m}^{2} {m o l}^{- 1})

A l^{3 +}

A l_{2} (S O_{4})_{3}

858

S . c m^{2}

m o l^{- 1}

S O_{4}^{2 -}

160

S . c m^{2}

m o l^{- 1}

25^{o}

\land_{m}^{\infty}

426.2

{c m}^{2}

{m o l}^{- 1}

\land_{m}^{\infty}

{c m}^{2}

{m o l}^{- 1}

C H_{3} C O O K

\land_{m}^{\infty}

149.86

{c m}^{2}

{m o l}^{- 1}

25^{o}

^0 m (H C l) = 425.9 Ω - 1 c m 2 m o l - 1

^0 m (N a C l) = 126.4 Ω - 1 c m 2 m o l - 1

^0 m (C H 3 C O O N a) = 91 Ω - 1 c m 2 m o l - 1

Ω - 1 c m 2 m o l - 1

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