From the top of a building of height $h,$ the angle of depression of an object on the ground is $\theta .$ What is the distance of the object from the foot of the building in terms of $h$ and $\theta ?$

Q. From the top of a building $h$ metre high, the angle of depression of an object on the ground has a measure $\theta$. The distance of the object from the building is

Q. Suppose you are shooting an arrow from the top of a building at a height of $6m$ to a target on the ground at an angle of depression of ${60}^{\circ }$. What is the distance between you and the object?

Q. The width of a road is $b$ feet., on one side of which there is a window $h$ feet height. A building in front of it subtends an angle $\theta$ at it. Prove that the height of the building is $\frac{(b^2+h^2)\sin \theta }{b\cos \theta +h\sin \theta }$

Q.

A man 1.8 metres tall, looking down from the top of a telephone tower sees the top of a building 10 metres high at an angle of depression 40° and the foot of the building at an angle of depression 60°. What is the height of the tower? How far is it away from the building?