Give the balanced chemical equations for the reaction of dilute sulphuric acid with:

$\mathrm{NaCl}$

1. Balanced chemical reaction

In any balanced chemical reaction, both charge, as well as mass, is balanced on the two sides of the reaction. Also, the number of atoms on both sides of the reactions is equal.

2. Reaction of Sulphuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$ with Sodium chloride $\left(\mathrm{NaCl}\right)$

When dilute Sulphuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$ reacts with Sodium chloride $\left(\mathrm{NaCl}\right)$ then the products that are formed are a salt referred to as Sodium sulphate $\left({\mathrm{Na}}_2{\mathrm{SO}}_4\right)$ and an acid called Hydrochloric acid $\left(\mathrm{HCl}\right)$.

The balanced chemical equation is shown below:

$$\begin{gathered} 2\mathrm{NaCl}\left(\mathrm{aq}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)\to {\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)+2\mathrm{HCl}\left(\mathrm{aq}\right) \\ \mathrm{Sodium}\mathrm{Sulphuric}\mathrm{Sodium}\mathrm{Hydrochloric} \\ \mathrm{chloride}\mathrm{acid}\mathrm{sulphate}\mathrm{acid} \end{gathered}$$