Given below are two statements:

Statement I: Potassium permangnate on heating at $573K$ forms potassium manganate.
Statement II: Both potassium permaganate and potassium manganate are tetrahedral and paramagnetic in nature.
In the light of the above statements, choose the most appropriate answer from the options given below:

The correct option is C Statement I is true but statement II is false
$\stackrel{+7}{KMn{O}_4}\stackrel{573K}{\to }\stackrel{+6}{K_{2}Mn{O}_4}+Mn{O}_2+O_2$
Diamagnetic Potassium Manganate
one unpaired electron
(Paramagnetic)

The outer electronic configuration of Mn is $3d^{5}4s^2$
In $KMn{O}_4$, Mn is in +7 oxidation state so it will be diamagnetic.
In $K_{2}Mn{O}_4$, Mn is in +6 oxidation state so it will have one unpaired electron so it will become paramagnetic.

Both $KMn{O}_4$ and $K_{2}Mn{O}_4$ are tetrahedral in shape.
Hence, (c) is the correct answer.