How do you find $3$ consecutive odd integers where the sum is $-141$?

Finding the $3$ consecutive odd integers:

Given that the sum of three consecutive odd integer $=-141$.

Let the first odd integer $=x$.

The next two consecutive odd integers will be $x+2andx+4$.

Then according to the statement

$\Rightarrow$ $x+(x+2)+(x+4)=-141$

$\Rightarrow$ $3x+6=-141$

$\Rightarrow$ $3x=-141-6$

$\Rightarrow$ $3x=-147$

$\Rightarrow$ $x=-\frac{147}{3}$

$\Rightarrow$ $x=-49$

Also find the value of $(x+2)$.

$(x+2)=-49+2$

$=-47$

And the value of $(x+4)$

$(x+4)=-49+4$

$=-45$

Hence three consecutive integers are $-49,-47,-45$

Therefore, the three consecutive integers are $-49,-47,-45$ where the sum is $-147$.