wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many 4 digit numbers greater than 5000 can be formed by using the digits 2, 3, 5, 6, 7 and 8 such that digits can get repeated?


A
765
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
432
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
864
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
874
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 864

When the repetition is allowed: All the places: Hundred’s, ten’s and unit’s can be filled by any of the digits: 2, 3, 5, 6, 7 or 8 i.e. in 6 ways.

Thousand’s place can be filled only in 4 ways. Hence no. numbers possible = 4×6×6×6 = 864.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Principle of Counting
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon