How many coulombs required to convert 1 mole of $H_{2}O$ to $O_2$?

The correct option is C $1.93\times {10}^{5}C$
Oxidation of $H_{2}O$ to $O_2$ is
$2H_{2}O=4H^{+}+O_2+4e^{-}$
Oxidation of 2 mole of water requires
= 96500 $\times$ 4C
Oxidation of 1 mole of water requires
$=\frac{96500\times 4}{2}=1.93\times {10}^{5}C$