How many faradays are required to reduce 1 mol of $C r_{2} O_{7}^{2 -}$ to $C r^{3 +}$ in acidic medium?

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Solution

The correct option is A 6

$1 m o l C r_{2} O_{7}^{2 -}$ requires 6 moles electron $= 6 F$ charge

$∴$ Number of Faraday's required $= 6$ .

Hence, option D is correct.

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