How many gram molecules of methane are required to produce $22gC{O}_2\left(g\right)$ after combustion?

The correct option is A 8

By unitary method and stoichiometric calculation,

$C{H}_4+2O_2\to C{O}_2+2H_{2}O$

1 mol of methane $\to$ 1 mol of carbon dioxide ($\to$indicates “gives”)

Hence 16 g of methane $\to$ 44g of carbon dioxide

So, x (say) grams of methane $\to$ 22g of carbon dioxide

By unitary method,

$x=\frac{16}{44}\times 22=8g$ of methane

Thus, 8 g of methane is required to produce 22 g of $C{O}_2$.

Hence, the correct option is $\text{A}$