How many integers greater than 1000 can be formed from the digits 0, 2, 3, and 5 if no digit is repeated in any number?

The correct option is B 18

• First digit can be filled in $3$ ways ($0$ cannot be first digit because it should be four digit number)
• second digit can be filled in $3$ ways
• Third digit can be filled in $2$ ways
• Fourth digit can be filled in $1$ way
• Therefore total number of distinct numbers will be $3\times 3\times 2\times 1=18$