How many molecules are present in 9g of water?

6.022

\times

10^{23}

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3.011

\times

10^{23}

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6.022

\times

10^{25}

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3.011

\times

10^{20}

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Solution

The correct option is B 3.011 $\times$ $10^{23}$
Molecular mass of water = 18 g
$∴$ 18 g = 6.022 $\times$ $10^{23}$ molecules of $H_{2} O$

$9 g = \frac{6.022}{2} \times 10^{23} m o l e c u l e s o f H_{2} O = 3.011 \times 10^{23} m o l e c u l e s o f H_{2} O$

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