How many moles of electron weight one kilogram?
a. 6.023 x 10^23
b. 1/9.108 x 10^31
c. 6.023/9.108 x 10^54
d. 1/9.108x6.023 x 10^8

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Solution

$M a s s o f a n e l e c t r o n = 9.1 \times 10^{- 31} K g S o, 1 K g w i l l h a v e t h e n u m b e r o f e l e c t r o n s = \frac{1}{9.1 \times 10^{- 31}} \times 1 = 0.1098 \times 10^{31} = 11 \times 10^{29} h e n c e, t h e a n s w e r i s (b) .$

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How many moles of electrons weight one kilogram?(Mass of electron = 9.1 Χ 10^-31kg, avogadro number = 6.023 Χ 10 ²³)

How many moles of electrons weigh one kilogram? (Mass of electron $= 9.108 \times 10^{- 31} k g$ , Avogadro’s number $= 6.023 \times 10^{23}$ )

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