How many moles of methane are required to produce $22 g {C O}_{2} (g)$ after combustion?

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Solution

Balanced equation for combustion of methane is,

$C H_{4} + 2 O_{2} ⟶ C O_{2} + 2 H_{2} O$
$16 g$ $44 g$
$\frac{16}{44} g$ $1 g$
$\frac{16}{44} \times 22 g$ $22 g$
$∴$ Number of moles of methane= $(\frac{16 \times 22}{44}) / 16 = 0.5$ .

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