How many moles of oxygen atoms is present in $80 %$ pure 20g of $C O_{2}$ ?

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0.5

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0.25

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0.73

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Solution

The correct option is D
0.73

80 $%$ pure 20g of $C O_{2}$ has $(20 \times \frac{80}{100}) g$ of $C O_{2}$ i.e., 16g of $C O_{2}$ is present.

For $C O_{2}$ , 44g of $C O_{2}$ = $32 g$ of $O_{2}$ = 2 moles of $O$ .

$∴$ $16 g$ of $C O_{2}$ = $(\frac{16 \times 2}{44})$ moles of O

= 0.727 moles of O

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