How many moles of sodium chloride present in $250mL$ of a $0.50MNaCI$ solution?

The correct option is A $0.125mol$
$NaCl$ Molarity $=\frac{\text{No.Of Moles}}{\text{Volume(li+)}}$

given data :

Volume $=250ml$

Molarity $=0.50M$

No. of moles $=$ Molarity $\times$ Volume $(li+)$

$=0.5\times 250\times {10}^{-3}$

$=0.725mol$