How many small cubes of edge length 2 cm each can be accommodated in a cubical box with edge length 6 cm?

The correct option is C 27
Given: Edge length of small cubes = 2 cm

Edge length of bigger cube in which small cubes can be accommodated = 6 cm

No. of small cubes that can be accommodated in the bigger cube

= $\frac{\text{Volume of large cube}}{\text{Volume of small cube}}$

$=\frac{6^3}{2^3}=\frac{216}{8}=27$

Hence, number of small cubes are 27.