How many three digit numbers can be formed from the digits $2, 3, 5, 6, 7$ and $9$ which are divisible by $5$ and none of the digits is repeated

5

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10

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15

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20

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Solution

The correct option is D $20$
$2, 3, 5, 6, 7, 9$
Divisible by $5$
No repetition
Three digit numbers
There are $2$ blanks and $5$ numbers
$\Rightarrow^{5} P_{2} \Rightarrow 5 \times 4 \Rightarrow 20$
Therefore $20$ Numbers are possible

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