How many times aqueous solution of pH $2$ is more acidic than aqueous solution of pH $4$?

The correct option is A Hundred times
We know that-

$pH=-lo{g}_{10}\left[H^{+}\right]$

$P{H}_1=2$

$⟹-{\log }_{10}[H^{+}{]}_1=2$

$⟹[H^{+}{]}_1={10}^{-2}$

$P{H}_2=4$

$⟹-{\log }_{10}[H^{+}{]}_2=4$

$⟹[H^{+}{]}_2={10}^{-4}$

Hence, $[H^{+}{]}_1=100[H^{+}{]}_2$

Answer-(A)