How many types of gametes are found in F₁ progeny of cross AA BB CC and aa bb cc

The correct option is B 8
Number of different types of gametes produced in an individual is $2^n$ where n is the number of Heterozygous gene pair in an individual.
Here the $F_1$ progeny of the cross would be AaBbCc. So, n = 3
Therefore, types of gametes possible is $2^3=8$

Types of gametes

1. ABC
2. ABc
3. Abc
4. aBC
5. aBc
6. AbC
7. abC
8. abc