How many unit cells are present in a cube-shaped ideal crystal of NaCl -of mass 1-00 g -Atomic masses- Na-23- Cl-35-5-2-57 x 1021-unit cells5-14-x 1021-unit cells1-28 x 1021-unit cells1-71 x 1021-unit cells

The correct option is A 2.57 x 1021 unit cells1/58.5× 6.023 × 10^23 = 1.029 × 10^22 A unit cell contains 4 Na^+ ion and 4 Cl^ ions ∴ Unit cell = 1.029 × 10^22 ...

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Standard XII

Chemistry

Application of Electrolysis

How many unit...

Question

How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g
[Atomic masses: Na=23, Cl=35.5]

2.57 x 10²¹unit cells

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5.14 x 10²¹unit cells

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1.28 x 10²¹unit cells

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1.71 x 10²¹ unit cells

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Solution

The correct option is A 2.57 x 10²¹unit cells
$\frac{1}{58.5} \times 6.023 \times 10^{23} = 1.029 \times 10^{22}$
A unit cell contains 4 $N a^{+}$ ion and 4 $C l^{-}$ ions
$∴$ Unit cell $= \frac{1.029 \times 10^{22}}{4} = 2.57 \times 10^{21}$ unit cell

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How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g [Atomic masses: Na=23, Cl=35.5]

The correct option is A 2.57 x 1021 unit cells158.5×6.023×1023=1.029×1022 A unit cell contains 4 Na+ ion and 4 Cl− ions ∴ Unit cell =1.029×10224=2.57×1021 unit cell

How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g
[Atomic masses: Na=23, Cl=35.5]

The correct option is A 2.57 x 10²¹unit cells
$\frac{1}{58.5} \times 6.023 \times 10^{23} = 1.029 \times 10^{22}$
A unit cell contains 4 $N a^{+}$ ion and 4 $C l^{-}$ ions
$∴$ Unit cell $= \frac{1.029 \times 10^{22}}{4} = 2.57 \times 10^{21}$ unit cell