How many words of $4$ constant & $3$ vowel can be formed from $6$ constant & $5$ vowels ?

The correct option is D

$Noneofthese$

Finding the Arrangements.

The counting digit of the word is $7$. Therefore, total number words is $7!$

Also, out of $6$ constant & $5$ vowels only $4$ constant & $3$ vowel is taken at time while making words

Therefore the total number of words can be formed

$$\begin{gathered} =7!\times {}^{6}C_4\times {}^{5}C_4 \\ =378000 \end{gathered}$$

Hence, the correct option is (D)