How much electricity in terms of Faraday is required to produce $100$ g of Ca from molten $C a C l_{2}$ ?

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Solution

The correct option is D $5$ F
We have to note that one mole of electron charge is equivalent to one Faraday.
Given reaction,
$C a C l_{2} \to C a^{2 +} + 2 C l^{-}$
Ca is undergoing oxidation i.e, $C a^{2 +} + 2 e^{-} \to C a$
We can observe that 40g of Ca takes $2 e^{-}$ charge,
So,1 mole of $C a (40 g) \equiv 2 F$
Now, 100g of $C a \equiv 5 F$

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