How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

The correct option is A $11.79g$
Sodium acetate is $C_2{H}_3{O}_{2}Na$

molar mass = 82 g/mol

Given: molarity, M=0.575 M, volume of solution, V=250 mL

number of moles, n=$\frac{mass}{molarmass}=\frac{m}{82}$

Using the relation: $M=\frac{n}{V}\times 1000$

substitute the values:

$0.575=\frac{m}{250\times 82}\times 1000$

$m=11.79$ g