How much quantity of electricity has to be passed through 200 ml of 0.5M $C u S O_{4}$ solution to completely deposit copper?

9.65 \times 10^{4} C

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1.93 \times 10^{4}

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3.86 \times 10^{5} C

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2.895 \times 10^{5} C

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Solution

The correct option is B $1.93 \times 10^{4}$
Moles of $C u S O_{4} = \frac{200 \times 0.5}{1000} = 0.1 M o l e$
Charge required to convert 0.1M $C u^{2 +}$ to $C u = 2 \times 96500 \times 0.1 = 1.93 \times 10^{4}$

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