How to solve this without a calculator $4.6\times {10}^{24}/6.022\times {10}^{23}=$

Q. If Avogadro number $N_A$, is changed from $6.022\times {10}^{23}{\text{mol}}^{-1}$ to $6.022\times {10}^{20}{\text{mol}}^{-1}$, this would change:

Q. If Avogadro’s number $N_A$, is changed from $6.022\times {10}^{23}{\text{mol}}^{-1}$ to $6.022\times {10}^{20}{\text{mol}}^{-1}$, this would change

Q. If Avagadro Number $N_A$ is changed from $6.022\times {10}^{23}{mol}^{-1}$ to $6.022\times {10}^{20}{mol}^{-1}$ this would change

Q. The Avogadro number ($N_A$), is changed from $6.022\times {10}^{23}$ $mo{l}^{-1}$ to $6.022\times {10}^{20}$ $mo{l}^{-1}$, this would change:

Q. 12 g C-12 contains $6.022\times {10}^{23}$ atoms of carbon.
(a) $6.022\times {10}^{23}$ is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more, $6.022\times {10}^{23}$ molecules of $C{O}_2$ or $6.022\times {10}^{23}$ molecules of $H_{2}O$?