(i) Calculate the volume of 320 g of SO₂ at stp (Atomic mass: S = 32 and O = 16)
(ii) State Gay-Lussac's Law of combining volumes.
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈). (Atomic mass: C = 14, O = 16, H = 1, Molar Volume = 22.4 dm³ at stp)

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Solution

(i) Number of moles of SO₂ in 320 g of SO₂ = $\frac{Mass of {SO}_{2}}{Molecular weight of {SO}_{2}} = \frac{320}{(32 + (16 \times 2))} = 5 mol$
At STP, one mole of SO₂ occupies 22.4 L of volume.
∴ Volume of five moles of SO₂ = (5 $\times$ 22.4) L = 112 L

(ii) Gay-Lussac's law states that reacting volumes of the gases bear a simple ratio with each other and to the volume of the gaseous products, when volumes are measured at same temperature and pressure.

(iii) Reaction of combustion of propane is:
C₃H₈ + 5O₂ $\to$ 3CO₂ + 4H₂O
So, for combustion of one mole of propane, five moles of oxygen is required.
Number of moles of propane in 8.8 g = $\frac{Mass of propane}{Molecular mass of propane} = \frac{8.8}{((3 \times 12) + (8 \times 1))} = 0.2 mol$
Number of moles of oxygen consumed by 0.2 mole of propane = (5 $\times$ 0.2) mol = 1 mol
One mole of oxygen at STP will occupy 22.4 L or 22.4 dm³.

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Similar questions

(a)

(i) Calculate the volume of 320 of $S O_{2}$ at STP. (Atomic mass : S = 32 and O = 16).
(ii) State Gay-Lussac's law of combining volume
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane $(C_{3} H_{8})$ (Atomic mass; C = 12, 0 = 16, H = 1, Molar volume $- 22.4 d m^{3}$

(b)

(i) An organic compound with vapour density = 94 contains
C = 12.67% H = 2.13 % and Br = 85.11% Find the molecular formula.
[Atomic mass ; C = 12, H = 1, Br = 80]
(ii) Calculate the mass of
(1) $10^{22}$ Atoms of sulphur.
(2) 0.1 mole of carbon dioxide.
[Atomic mass; S = 32, C = 12 and O = 16 and Avogadro's number $= 6 \times 10^{23}$

Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈).

[Atomic mass: C = 12, O = 16, H = 1, Molar volume = 22.4 dm³ at stp]

Q. The volume of oxygen required for the complete combustion of 8.8 g of propane

(C_{3} H_{8})

is:

[

C = 12, O = 16, H = 1,

Molar Volume

= 22.4

^{3}

at S.T.P]

Calculate the volume of 320 g of SO₂ at STP.

[Atomic mass: S = 32 and 0=16]

Q. Calculate volume of oxygen at STP required to complete the combustion of 8 L of methane.

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