Identify the values of x, y and z for the following reaction to be balanced.
${\text{xN}}_2+{\text{yH}}_2\to {\text{zNH}}_3$

The correct option is C x=1, y=3, z=2
${\text{N}}_2+{\text{H}}_2\to {\text{NH}}_3$
Number of N atoms on the reactant side: 2
Number of N atoms on the product side: 1
On multiplying the product side with 2,
${\text{N}}_2+{\text{H}}_2\to {\text{2NH}}_3$
Now, the number of H atoms on reactant side is : 2
Number of H atoms on product side is : $2\times 3=6$
On multiplying the reactant side with 3,
${\text{N}}_2+{\text{3H}}_2\to {\text{2NH}}_3$
Now, the number of N and H atoms on both sides are equal and the equation is balanced. Thus, x= 1, y=3, z=2