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Question

If 11 A.M.'s are inserted between 28 and 10, then the number of integral A.M.'s is

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Solution

Given : 11 A.M.'s are inserted between 28 and 10, so
d=102811+1=32
Now, let An be the nth A.M., so
An=283n2
For integral A.M.'s, n should be even.
n=2,4,6,8,10

Hence, the number of integral A.M.'s is 5.

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