If 1gram of sulphur dioxide contains x molecules, what will be the number of molecules in 1gram of methane?

1 mole of $S{O}_2=64g$
1g of $S{O}_2$ = -----mole?
$=\frac{1}{64}mole$
From the given data $\frac{1}{64}$ moles sulphur dioxide contain x molecules
We know that equal moles of all gases will have equal number of molecules.
Hence $\frac{1}{64}$ moles of Methane Contains x molecules of methane
Now we should find out the number of moles in 1g of methane
1 mole of methane = 16g
1g of methane = ------Mole?
$=\frac{1}{16}mole$
Since,
$\frac{1}{64}$ mole of methane = x molecules
$\frac{1}{16}$ mole of methane contains = -------molecules?
$=x\times \frac{64}{16}=4x$ molecules